sample of 35 gas grills has a mean price of $637.50 and a standard deviation of $59.30?

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hunkyscutie asked:


you are given the sample mean and the sample standard deviation. use this information to construct the 90% and 95% confidence intervals for the population mean.

a sample of 35 gas grills has a mean price of $637.50 and a standard deviation of $59.30.

the 90% confidence interval is ___________ ______________

the 95% confidence interval is ___________ ______________

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  • No Responses to “sample of 35 gas grills has a mean price of $637.50 and a standard deviation of $59.30?”

    1. Bleaksky Says:

      Sample…………….35
      Stdev………………..59.3
      Mean………………..637.5
      Z-score…………….1.645
      Standard error….10.02352946
      Margin of error….16.48870596
      CI (90%)……………621.01 to 653.99

      Sample…………….35
      Stdev……………….59.3
      Mean………………..637.5
      Z-score…………….1.96
      Standard error….10.02352946
      Margin of error….19.64611774
      CI (95%)……………617.85 to 657.15